(x^2-16)/(x^2-3x-4)=0

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Solution for (x^2-16)/(x^2-3x-4)=0 equation: 


D( x )

x^2-(3*x)-4 = 0

x^2-(3*x)-4 = 0

x^2-(3*x)-4 = 0

x^2-3*x-4 = 0

x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+3)/(1*2) or x = (3-25^(1/2))/(1*2)

x = 4 or x = -1

x in (-oo:-1) U (-1:4) U (4:+oo)

(x^2-16)/(x^2-(3*x)-4) = 0

(x^2-16)/(x^2-3*x-4) = 0

x^2-3*x-4 = 0

x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+3)/(1*2) or x = (3-25^(1/2))/(1*2)

x = 4 or x = -1

(x+1)*(x-4) = 0

(x^2-16)/((x+1)*(x-4)) = 0

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in { 4} 

x = -4

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